Bloom Filter Algorithm of Big Data Analysis Using Python
SourceCode :
def sum(inp):
s = 0
for ch in inp:
s = s+ord(ch)
return s
def h1(inp):
s = sum(inp)
return(3*s+5)%15
def h2(inp):
s = sum(inp)
return(7*s+3)%13
bit_vector = [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]
while True:
inp = raw_input("Enter the string :")
if(inp == 'stop'):
break
print("H1",h1(inp),"H2",h2(inp))
bit_vector[h1(inp)] = 1
bit_vector[h2(inp)] = 1
print(bit_vector)
inp = raw_input("\n Enter a string to check the memebership : ")
if(bit_vector[h1(inp)] == 1 and bit_vector[h2(inp)] == 1 ):
print(inp,"may be present")
else:
print(inp,"not present")
OUTPUT:
Enter the string : Ashish
('H1', 5, 'H2', 11)
[0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 0]
Enter the string :Rahul
('H1', 14, 'H2', 10)
[0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1, 1, 0, 0, 1]
Enter the string :Aditya
('H1', 2, 'H2', 6)
[0, 0, 1, 0, 0, 1, 1, 0, 0, 0, 1, 1, 0, 0, 1]
Enter the string :Vishal
('H1', 5, 'H2', 5)
[0, 0, 1, 0, 0, 1, 1, 0, 0, 0, 1, 1, 0, 0, 1]
Enter the string :stop
Enter a string to check the memebership : Vishal
('Vishal', 'may be present')
('H1', 5, 'H2', 11)
[0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 0]
Enter the string :Rahul
('H1', 14, 'H2', 10)
[0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1, 1, 0, 0, 1]
Enter the string :Aditya
('H1', 2, 'H2', 6)
[0, 0, 1, 0, 0, 1, 1, 0, 0, 0, 1, 1, 0, 0, 1]
Enter the string :Vishal
('H1', 5, 'H2', 5)
[0, 0, 1, 0, 0, 1, 1, 0, 0, 0, 1, 1, 0, 0, 1]
Enter the string :stop
Enter a string to check the memebership : Vishal
('Vishal', 'may be present')
Comments
Post a Comment